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Proof step 5 from proof write-new-app-nodups (previous step)

# ax0 = # ndx0, new(ax1, fs0[ax0, ndx0]), dups(ax0) ∨ dups(ax1) ∨ (∃ adr. adr ∈ ax0 ∧ adr ∈ ax1) ⊦ dups(ax1), dups(ax0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information