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Proof step 8 from proof write-new-app-nodups (previous step)

# ax0 = # ndx0, adr ∈ ax1, adr ∈ ax0, ∀ adr. adr ∈ ax1 → ¬ adr ∈ fs0[ax0, ndx0] ⊦ dups(ax1), dups(ax0)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: adr

Additional information

Used simplifier rules: in-write: # ax = # ndx ⊦ adr ∈ fs[ax, ndx] ↔ adr ∈ fs ∨ adr ∈ ax; Used terms: adr