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Proof step 5 from proof write-new-app (previous step)

# ax0 = # ndx0, new(ax0, fs0), new(ax, fs0[ax0, ndx0]), ∀ ax0, ndx0, fs0. # ax0 = # ndx0 ∧ new(ax, fs0[ax0, ndx0]) ∧ new(ax0, fs0) → new(ax, fs0) ⊦ new(ax, fs0), adr ∈ ax0, adr ∈ fs0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: ax0, ndx0, fs0

Additional information

Used terms: ax0, ndx0, fs0