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Proof step 9 from proof write-shift (previous step)

# ax0 = # ndx0, ∀ ndx, fs, adr, nd. # ndx0 = # ndx → fs[adr, nd][ax0, ndx] = fs[ax0, ndx][adr, nd] ∨ adr ∈ ax0 ⊦ fs[adr0, nd0][adr, nd][ax0, ndx0] = fs[adr0, nd0][ax0, ndx0][adr, nd], adr0 = adr, adr ∈ ax0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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