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Proof step 17 from proof crash-neutral-add3 (previous step)

ro.inodes?, fo.inodes?, log-cons(log, fs), node-cons(nd3.key, nd3), node-cons(nd0.key, nd0), node-cons(nd2.key, nd2), ri-cons(ri, fs), ri-inj(ri), ri-inj(fi) ⊦ ∃ err0. ⌊err0⌋ ∧ ⟨err := err0; adr1 := ?, adr2 := ?, adr3 := ?; boolvar := ?⟩ boolvar, ⟨boolvar := ?⟩ boolvar

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

pos: right 2

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