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Proof step 12 from proof crash-neutral-add5 (previous step)

fo.inodes?, ro.inodes?, log-cons(log, fs), node-cons(nd4.key, nd4), node-cons(nd5.key, nd5), node-cons(nd1.key, nd1), node-cons(nd6.key, nd6), node-cons(nd7.key, nd7), ri-cons(ri, fs), ri-inj(fi), ri-inj(ri) ⊦ ∃ err0. ⌊err0⌋ ∧ ⟨err := err0; adr8 := ?, adr7 := ?, adr6 := ?, adr0 := ?, adr := ?; boolvar := ?⟩ boolvar, ∃ adr4, adr5, adr9, adr10, adr11. ¬ adr4 ∈ fs ∧ ¬ adr5 ∈ fs ∧ ¬ adr9 ∈ fs ∧ ¬ adr10 ∈ fs ∧ ¬ adr11 ∈ fs ∧ adr4 ≠ adr5 ∧ adr4 ≠ adr9 ∧ adr4 ≠ adr10 ∧ adr4 ≠ adr11 ∧ adr5 ≠ adr9 ∧ adr5 ≠ adr10 ∧ adr5 ≠ adr11 ∧ adr9 ≠ adr10 ∧ adr9 ≠ adr11 ∧ adr10 ≠ adr11 ∧ ⟨adr8 := adr4, adr7 := adr5, adr6 := adr9, adr0 := adr10, adr := adr11; fs1 := fs[adr8, nd7][adr7, nd6][adr6, nd1][adr0, nd5][adr, nd4], log1 := ((((log + adr8 ') + adr7 ') + adr6 ') + adr0 ') + adr ', err := ESUCCESS; boolvar := ?⟩ (boolvar ∧ fs = fs1 ∧ log = log1), adr = adr0, adr = adr1, adr = adr2, adr = adr3, adr0 = adr1, adr0 = adr2, adr0 = adr3, adr1 = adr2, adr1 = adr3, adr2 = adr3, adr ∈ fs, adr0 ∈ fs, adr1 ∈ fs, adr2 ∈ fs, adr3 ∈ fs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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