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Proof step 7 from proof inv-add3 (previous step)

adr = adr5, adr4 = adr6, nd = nd2, nd1 = nd3, ro.inodes?, fo.inodes?, log-cons(log, fs), new(adr1 ' + (adr2 ' + adr3), fs), node-cons(nd3.key, nd3), node-cons(nd0.key, nd0), node-cons(nd2.key, nd2), ri-cons(ri, fs), ri-inj(ri), ri-inj(fi) ⊦ ⟪adr4 := adr1, adr0 := adr2, adr := adr3; fs := fs[adr4, nd1][adr0, nd0][adr, nd], log := ((log + adr4) + adr0) + adr, err := ESUCCESS; boolvar := ?⟫ (log-cons(log, fs) ∧ ri-cons(ri, fs)), dups(adr1 ' + adr2 ' + adr3 ')

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 8:
adr = adr5, adr4 = adr6, nd = nd2, nd1 = nd3, fo.inodes?, ro.inodes?, log-cons(log, fs), new(adr1 ' + (adr2 ' + adr3), fs), node-cons(nd2.key, nd2), node-cons(nd0.key, nd0), node-cons(nd3.key, nd3), ri-cons(ri, fs), ri-inj(fi), ri-inj(ri) ⊦ ⟪fs := fs[adr1, nd1][adr2, nd0][adr3, nd], log := ((log + adr1) + adr2) + adr3, err := ESUCCESS; boolvar := ?⟫ (log-cons(log, fs) ∧ ri-cons(ri, fs)), dups(adr1 ' + adr2 ' + adr3 ')

Proof step 7 from proof inv-add3 (previous step)

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

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