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Proof step 55 from proof inv-add4 (previous step)

ro.inodes?, fo.inodes?, log-cons(log, fs), node-cons(fs[adr].key, fs[adr]), node-cons(nd6.key, nd6), node-cons(nd5.key, nd5), node-cons(nd4.key, nd4), node-cons(nd3.key, nd3), ri-cons(ri, fs), ri-inj(ri), ri-inj(fi), adr ∈ fs, adr ∈ log ⊦ ri[key] = adr4, ri[key] = adr3, ri[key] = adr2, adr = adr3, adr1 = adr2, adr1 = adr3, adr1 = adr4, adr2 = adr3, adr2 = adr4, adr3 = adr4, node-cons(fs[adr1, nd6][adr2, nd5][adr].key, fs[adr1, nd6][adr2, nd5][adr]), adr4 ∈ fs, adr3 ∈ fs, adr2 ∈ fs, adr1 ∈ fs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 56:
fo.inodes?, ro.inodes?, log-cons(log, fs), node-cons(nd3.key, nd3), node-cons(nd4.key, nd4), node-cons(nd5.key, nd5), node-cons(nd6.key, nd6), node-cons(fs[adr].key, fs[adr]), ri-cons(ri, fs), ri-inj(fi), ri-inj(ri), adr ∈ log, adr ∈ fs ⊦ ri[key] = adr2, ri[key] = adr3, ri[key] = adr4, adr1 = adr4, adr1 = adr3, adr1 = adr2, adr2 = adr4, adr2 = adr3, adr3 = adr4, node-cons(fs[adr1, nd6][adr2, nd5][adr].key, fs[adr1, nd6][adr2, nd5][adr]), adr1 ∈ fs, adr2 ∈ fs, adr3 ∈ fs, adr4 ∈ fs

Proof step 55 from proof inv-add4 (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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