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Proof step 5 from proof inv-contains (previous step)

boolvar ↔ boolvar1, boolvar0 ↔ boolvar2, ro.inodes?, fo.inodes?, log-cons(log, fs), ri-inj(ri), ri-inj(fi) ⊦ ⟪choose err0 with ⌊err0⌋ ∨ err0 = ESUCCESS in err := err0; if err = ESUCCESS then boolvar := key ∈ ri else boolvar := ?⟫ true

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Proof step 6:
boolvar0 ↔ boolvar2, boolvar ↔ boolvar1, fo.inodes?, ro.inodes?, log-cons(log, fs), ri-inj(fi), ri-inj(ri), ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪err := err0; if err = ESUCCESS then boolvar := key ∈ ri else boolvar := ?⟫ true
Proof step 10:
boolvar0 ↔ boolvar2, boolvar ↔ boolvar1, fo.inodes?, ro.inodes?, log-cons(log, fs), ri-inj(fi), ri-inj(ri) ⊦ ∃ err0. ⌊err0⌋ ∨ err0 = ESUCCESS

Proof step 5 from proof inv-contains (previous step)

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Rule argument

Additional information