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Proof step 10 from proof file-node-cons-variant1-01 (previous step)

inodekey(ino) ∈ ri0, ∀ ino. (inodekey(ino) ∈ ri ∧ ¬ fs[ri[inodekey(ino)]].directory → fs[ri[inodekey(ino)]].nsubdirs = 0) → inodekey(ino) ∈ ri0 ∧ ¬ fs0[ri0[inodekey(ino)]].directory → fs0[ri0[inodekey(ino)]].nsubdirs = 0, ∀ ino. inodekey(ino) ∈ ri ∧ ¬ fs[ri[inodekey(ino)]].directory → fs[ri[inodekey(ino)]].nsubdirs = 0 ⊦ fs0[ri0[inodekey(ino)]].nsubdirs = 0, fs0[ri0[inodekey(ino)]].directory

User applied rule all left

And obtained the following new goals

Proof step 11:
inodekey(ino) ∈ ri0, (inodekey(ino) ∈ ri ∧ ¬ fs[ri[inodekey(ino)]].directory → fs[ri[inodekey(ino)]].nsubdirs = 0) → inodekey(ino) ∈ ri0 ∧ ¬ fs0[ri0[inodekey(ino)]].directory → fs0[ri0[inodekey(ino)]].nsubdirs = 0, ∀ ino. inodekey(ino) ∈ ri ∧ ¬ fs[ri[inodekey(ino)]].directory → fs[ri[inodekey(ino)]].nsubdirs = 0 ⊦ fs0[ri0[inodekey(ino)]].nsubdirs = 0, fs0[ri0[inodekey(ino)]].directory

Rule argument

pos: left 2 terms: ino abort: F discard: T computed: T

Additional information

Used terms: ino