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Proof step 22 from proof in-ri-update-in-ri (previous step)

# ax1 = # ax0, key ∈ ri, ax1.toSet ⊆ range ri, key ∈ ri → ri[key] ∈ fs ∧ key-cons(key, fs[ri[key]]) ⊦ fs[ri[key]].key ∈ ri, fs[ri[key]].key ∈ keys(fs, ax1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
# ax1 = # ax0, key-cons(key, fs[ri[key]]), key ∈ ri, ri[key] ∈ fs, ax1.toSet ⊆ range ri ⊦ fs[ri[key]].key ∈ keys(fs, ax1), fs[ri[key]].key ∈ ri

Proof step 22 from proof in-ri-update-in-ri (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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