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Proof step 16 from proof index-update-dom (previous step)

# ax0 = # ax1, adr ∈ ax0, ∀ key. key ∈ ri → ri[key] ∈ fs ∧ key-cons(key, fs[ri[key]]), ∃ key. key ∈ ri ∧ ri[key] = adr ⊦ fs[adr].key ∈ ri

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information