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Proof step 18 from proof index-update-dom (previous step)

# ax0 = # ax1, ri[key] ∈ ax0, key ∈ ri, key ∈ ri → ri[key] ∈ fs ∧ key-cons(key, fs[ri[key]]) ⊦ fs[ri[key]].key ∈ ri

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information