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Proof step 11 from proof log-cons-app (previous step)

adr ∈ log0 ∨ adr ∈ log1 → adr ∈ fs ∧ node-cons(fs[adr].key, fs[adr]), ∀ adr. adr ∈ log0 ∨ adr ∈ log1 → adr ∈ fs ∧ node-cons(fs[adr].key, fs[adr]) ⊦ (adr ∈ log0 → adr ∈ fs ∧ node-cons(fs[adr].key, fs[adr])) ∧ (adr0 ∈ log1 → adr0 ∈ fs ∧ node-cons(fs[adr0].key, fs[adr0]))

User applied rule all left

And obtained the following new goals

Proof step 12:
adr ∈ log0 ∨ adr ∈ log1 → adr ∈ fs ∧ node-cons(fs[adr].key, fs[adr]), adr0 ∈ log0 ∨ adr0 ∈ log1 → adr0 ∈ fs ∧ node-cons(fs[adr0].key, fs[adr0]), ∀ adr. adr ∈ log0 ∨ adr ∈ log1 → adr ∈ fs ∧ node-cons(fs[adr].key, fs[adr]) ⊦ (adr ∈ log0 → adr ∈ fs ∧ node-cons(fs[adr].key, fs[adr])) ∧ (adr0 ∈ log1 → adr0 ∈ fs ∧ node-cons(fs[adr0].key, fs[adr0]))

Rule argument

pos: left 2 terms: adr0 abort: F discard: F computed: T

Additional information

Used terms: adr0