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Proof step 32 from proof ri-cons-copy-new (previous step)

# kx = # ax, new(ax, fs), key ∈ ri, kx.toSet ⊆ dom ri, ∀ key. key ∈ ri → ri[key] ∈ fs ∧ key-cons(key, fs[ri[key]]) ⊦ dups(ax), dups(kx), key-cons(key, fs[ri[key]]), ri[key] ∈ ax, key ∈ kx

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: key

Additional information

Used terms: key