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Proof step 3 from proof ubifs-cons-notin-dels (previous step)

ubifs-cons(fs, ri, ro, fi, fo, log), adr ∈ ri ⊖ ks ⊦ adr ∈ fs

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: aubifs-base name: notin-dels seq: ⊦ ¬ adr ∈ ri → ¬ adr ∈ ri ⊖ ks subst: [ks, ri, adr] → [ks, ri, adr] flags: <all paths>

Additional information

Used simplifier rules: ubifs-adr-in-ri: ⊦ adr ∈ ri ∧ ubifs-cons(fs, ri, ro, fi, fo, log) → adr ∈ fs; Used terms: ks, ri, adr