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Proof step 12 from proof ubifs-cons-ri-inj (previous step)

fs[ri[key0]].key = key0, ri[key] = ri[key0], ro.inodes?, fo.inodes?, key-cons(key, fs[ri[key0]]), ri[key0] ∈ fs, key0 ∈ ri, key ∈ ri, ro ⊆ dom ri, fo ⊆ dom fi, key0.inode? → fs[ri[key0]].inode? ∧ key0.ino ≠ 0, key0.dentry? → fs[ri[key0]].dentry?, key0.data? → fs[ri[key0]].data?, ∀ adr. adr ∈ log → adr ∈ fs ∧ node-cons(fs[adr].key, fs[adr]), ∀ key. key ∈ ri → ri[key] ∈ fs ∧ node-closed(fs[ri[key]], ri, fs, ro), ∀ key. key ∈ ri → ri[key] ∈ fs ∧ key-cons(key, fs[ri[key]]) ⊦ key = key0, dups(log), inodekey(0) ∈ ri

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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