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Proof step 6 from proof ubifs-in-fs (previous step)

fo.inodes?, ro.inodes?, key ∈ ri, fo ⊆ dom fi, ro ⊆ dom ri, ∀ key. key ∈ ri → ri[key] ∈ fs ∧ key-cons(key, fs[ri[key]]), ∀ key. key ∈ ri → ri[key] ∈ fs ∧ node-closed(fs[ri[key]], ri, fs, ro), ∀ adr. adr ∈ log → adr ∈ fs ∧ node-cons(fs[adr].key, fs[adr]) ⊦ dups(log), inodekey(0) ∈ ri, ri[key] ∈ fs

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 7 terms: key

Additional information

Used terms: key