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Proof step 2 from proof ubifs-log-nodups-add3 (previous step)

dups(log + adr0 ' + adr1 ' + adr2 '), ubifs-cons(fs, ri, ro, fi, fo, log) ⊦ adr0 = adr2, adr0 = adr1, adr1 = adr2, adr2 ∈ fs, adr1 ∈ fs, adr0 ∈ fs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information