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Proof step 30 from proof ubifs-log-nodups-add5 (previous step)

fo.inodes?, ro.inodes?, adr0 ∈ log, fo ⊆ dom fi, ro ⊆ dom ri, ∀ key. key ∈ ri → ri[key] ∈ fs ∧ key-cons(key, fs[ri[key]]), ∀ key. key ∈ ri → ri[key] ∈ fs ∧ node-closed(fs[ri[key]], ri, fs, ro), ∀ adr. adr ∈ log → adr ∈ fs ∧ node-cons(fs[adr].key, fs[adr]) ⊦ adr1 = adr2, adr1 = adr3, adr1 = adr4, adr2 = adr3, adr2 = adr4, adr3 = adr4, dups(log), inodekey(0) ∈ ri, adr0 ∈ fs, adr1 ∈ fs, adr2 ∈ fs, adr3 ∈ fs, adr4 ∈ fs, adr4 ∈ log, adr3 ∈ log, adr2 ∈ log, adr1 ∈ log

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 8 terms: adr0

Additional information

Used terms: adr0