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Proof step 5 from proof ubifs-log-nodups-add5 (previous step)

ro.inodes?, fo.inodes?, dups(log + adr0 ' + adr1 ' + adr2 ' + adr3 ' + adr4 '), log-cons(log, fs), ri-closed(ri, fs, ro), ri-cons(ri, fs), ro ⊆ dom ri, fo ⊆ dom fi ⊦ adr0 = adr4, adr0 = adr3, adr0 = adr2, adr0 = adr1, adr1 = adr4, adr1 = adr3, adr1 = adr2, adr2 = adr4, adr2 = adr3, adr3 = adr4, dups(log), adr4 ∈ fs, adr3 ∈ fs, adr2 ∈ fs, adr1 ∈ fs, adr0 ∈ fs, inodekey(0) ∈ ri

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
fo.inodes?, ro.inodes?, dups(log + adr0 ' + adr1 ' + adr2 ' + adr3 ' + adr4 '), fo ⊆ dom fi, ro ⊆ dom ri, ∀ key. key ∈ ri → ri[key] ∈ fs ∧ key-cons(key, fs[ri[key]]), ∀ key. key ∈ ri → ri[key] ∈ fs ∧ node-closed(fs[ri[key]], ri, fs, ro), ∀ adr. adr ∈ log → adr ∈ fs ∧ node-cons(fs[adr].key, fs[adr]) ⊦ adr0 = adr1, adr0 = adr2, adr0 = adr3, adr0 = adr4, adr1 = adr2, adr1 = adr3, adr1 = adr4, adr2 = adr3, adr2 = adr4, adr3 = adr4, dups(log), inodekey(0) ∈ ri, adr0 ∈ fs, adr1 ∈ fs, adr2 ∈ fs, adr3 ∈ fs, adr4 ∈ fs

Rule argument

Additional information

Used simplifier rules: ri-cons: ⊦ ri-cons(ri, fs) ↔ (∀ key. key ∈ ri → ri[key] ∈ fs ∧ key-cons(key, fs[ri[key]]));%ri-closed: ⊦ ri-closed(ri, fs, ro) ↔ (∀ key. key ∈ ri → ri[key] ∈ fs ∧ node-closed(fs[ri[key]], ri, fs, ro));%log-cons: ⊦ log-cons(log, fs) ↔ (∀ adr. adr ∈ log → adr ∈ fs ∧ node-cons(fs[adr].key, fs[adr]));