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Proof step 2 from proof ubifs-ri-cons (previous step)

ubifs-cons(fs, ri, ro, fi, fo, log) ⊦ ri-cons(ri, fs)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
ubifs-cons(fs, ri, ro, fi, fo, log), key ∈ ri ⊦ key-cons(key, fs[ri[key]])

Rule argument

Additional information

Used simplifier rules: ri-cons: ⊦ ri-cons(ri, fs) ↔ (∀ key. key ∈ ri → ri[key] ∈ fs ∧ key-cons(key, fs[ri[key]]));%ubifs-in-fs: ⊦ key ∈ ri ∧ ubifs-cons(fs, ri, ro, fi, fo, log) → ri[key] ∈ fs;