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Proof step 5 from proof abs-log-except-refsize (previous step)

gstore1 =○refsize gstore0, ∀ gstore1, gstore0. gstore1 =○refsize gstore0 → abs-log(nx0, gstore1) = abs-log(nx0, gstore0) ⊦ gstore1[lnum].ladrlist.to-adr(lnum) + abs-log(nx0, gstore1) = gstore0[lnum].ladrlist.to-adr(lnum) + abs-log(nx0, gstore0)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 6:
gstore1[lnum] = groupblock(gndx, lax, m), gstore1 =○refsize gstore0, ∀ gstore1, gstore0. gstore1 =○refsize gstore0 → abs-log(nx0, gstore1) = abs-log(nx0, gstore0) ⊦ lax.to-adr(lnum) + abs-log(nx0, gstore1) = gstore0[lnum].ladrlist.to-adr(lnum) + abs-log(nx0, gstore0)

Rule argument

spec: ablock, inst: group-store name: elim seq: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m) subst: [gblock, gndx, lax, m] → [gstore1[lnum], gndx, lax, m]

Additional information

Used simplifier rules: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m); (elim) Used terms: gstore1[lnum], gndx, lax, m