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Proof step 7 from proof abs-log-no-change-eq (previous step)

gstore0[lnum] = groupblock(gndx, lax, m), gstore1[lnum] = groupblock(gndx0, lax0, m0), ∀ gstore0, gstore1. (∀ n. (n ∈ gstore0 ↔ n ∈ gstore1) ∧ (n ∈ gstore0 → gstore1[n].gndlist = gstore0[n].gndlist ∧ gstore1[n].ladrlist = gstore0[n].ladrlist)) → abs-log(nx0, gstore0) = abs-log(nx0, gstore1), ∀ n. (n ∈ gstore0 ↔ n ∈ gstore1) ∧ (n ∈ gstore0 → gstore1[n].gndlist = gstore0[n].gndlist ∧ gstore1[n].ladrlist = gstore0[n].ladrlist) ⊦ lax.to-adr(lnum) + abs-log(nx0, gstore0) = lax0.to-adr(lnum) + abs-log(nx0, gstore1)

User applied rule all left

And obtained the following new goals

Proof step 8:
gstore1[lnum] = groupblock(gndx0, lax0, m0), gstore0[lnum] = groupblock(gndx, lax, m), (∀ n. (n ∈ gstore0 ↔ n ∈ gstore1) ∧ (n ∈ gstore0 → gstore1[n].gndlist = gstore0[n].gndlist ∧ gstore1[n].ladrlist = gstore0[n].ladrlist)) → abs-log(nx0, gstore0) = abs-log(nx0, gstore1), ∀ n. (n ∈ gstore0 ↔ n ∈ gstore1) ∧ (n ∈ gstore0 → gstore1[n].gndlist = gstore0[n].gndlist ∧ gstore1[n].ladrlist = gstore0[n].ladrlist) ⊦ lax.to-adr(lnum) + abs-log(nx0, gstore0) = lax0.to-adr(lnum) + abs-log(nx0, gstore1)

Rule argument

pos: left 3 terms: gstore0, gstore1 abort: F discard: T computed: F

Additional information

Used terms: gstore0, gstore1