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Proof step 6 from proof adr-in-ri-in-gstore (
previous step
)
key ∈ ri, ∀ key0. key0 ∈ ri → ri[key0] ∈ gstore ↓ ∧ ¬ ri[key0].lnum ∈ ginval ∧ key-cons(key0, nodes(gstore ↓, ginval)[ri[key0]]) ⊦ ri[key] ∈ gstore
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 2 terms: key
Additional information
Used simplifier rules: down-store-notin-notin: ⊦ ¬ adr ∈ gstore → ¬ adr ∈ gstore ↓; Used terms: key