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Proof step 23 from proof down-except-refsize (previous step)

gstore1 ↓[n] = groupblock(gndx, lax, m), groupblock (prefixn(valid-group-nodes(gstore0[n].gndlist), gstore0[n].gndlist), prefixn(valid-group-nodes(gstore0[n].gndlist), gstore0[n].ladrlist), gstore0[n].ref-size) = groupblock(gndx0, lax0, m0), n ∈ gstore0, ∀ n. (n ∈ gstore1 ↔ n ∈ gstore0) ∧ gstore1[n].gndlist = gstore0[n].gndlist ∧ gstore1[n].ladrlist = gstore0[n].ladrlist ⊦ n ∈ gstore1 ∧ gndx = gndx0 ∧ lax = lax0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
gstore1 ↓[n] = groupblock(gndx, lax, m), n ∈ gstore0, ∀ n. (n ∈ gstore1 ↔ n ∈ gstore0) ∧ gstore1[n].gndlist = gstore0[n].gndlist ∧ gstore1[n].ladrlist = gstore0[n].ladrlist ⊦ n ∈ gstore1 ∧ gndx = prefixn(valid-group-nodes(gstore0[n].gndlist), gstore0[n].gndlist) ∧ lax = prefixn(valid-group-nodes(gstore0[n].gndlist), gstore0[n].ladrlist)

Rule argument

Additional information

Used simplifier rules: ⊦ groupblock(gndx, lax, m) = groupblock(gndx0, lax0, m0) ↔ gndx = gndx0 ∧ lax = lax0 ∧ m = m0; (ws)