[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 6 from proof down-except-refsize (previous step)

gstore1 =○refsize gstore0 ⊦ (n ∈ gstore1 ↔ n ∈ gstore0) ∧ gstore1 ↓[n].gndlist = gstore0 ↓[n].gndlist ∧ gstore1 ↓[n].ladrlist = gstore0 ↓[n].ladrlist

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 7:
gstore1 ↓[n] = groupblock(gndx, lax, m), gstore1 =○refsize gstore0 ⊦ (n ∈ gstore1 ↔ n ∈ gstore0) ∧ gndx = gstore0 ↓[n].gndlist ∧ lax = gstore0 ↓[n].ladrlist

Rule argument

spec: ablock, inst: group-store name: elim seq: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m) subst: [gblock, gndx, lax, m] → [gstore1 ↓[n], gndx, lax, m]

Additional information

Used simplifier rules: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m); (elim) Used terms: gstore1 ↓[n], gndx, lax, m