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Proof step 5 from proof down-store-at-diff (previous step)

⊦ (gstore \ ginval)↓[n] = gstore ↓[n], n ∈ ginval, n ∈ gstore \ ginval

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⊦ (gstore \ ginval)↓[n] = gstore ↓[n], n ∈ ginval, n ∈ gstore

Rule argument

Additional information

Used simplifier rules: ⊦ n ∈ gstore \ ns ↔ n ∈ gstore ∧ ¬ n ∈ ns; (ws)