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Proof step 9 from proof ginval-extract-nodes (previous step)

@(m0, m1) ∈ gstore[m].ladrlist, m ∈ gstore ⊦ nodes(gstore, ginval)[@(m, m0, m1)] = nodes(gstore \ ginval, ginval)[@(m, m0, m1)], m ∈ ginval

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 10:
gstore[m] = groupblock(gndx, lax, m2), m ∈ gstore, @(m0, m1) ∈ lax ⊦ nodes(gstore, ginval)[@(m, m0, m1)] = nodes(gstore \ ginval, ginval)[@(m, m0, m1)], m ∈ ginval

Rule argument

spec: ablock, inst: group-store name: elim seq: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m) subst: [gblock, gndx, lax, m] → [gstore[m], gndx, lax, m2]

Additional information

Used simplifier rules: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m); (elim) Used terms: gstore[m], gndx, lax, m2