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Proof step 13 from proof gstore-dom-eq-hole (previous step)

n0 ∈ gstore0 ↔ n0 ∈ gstore1, gstore0 \ (∅ ++ n) = gstore1 \ (∅ ++ n), n ∈ gstore0 ⊦ (n0 ∈ gstore1 ↔ n0 ∈ gstore0) ∧ (n0 ∈ gstore1 → gstore1[n0] = gstore0[n, gstore1[n]][n0])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
gstore0 \ (∅ ++ n) = gstore1 \ (∅ ++ n), n ∈ gstore0, n0 ∈ gstore1, n0 ∈ gstore0 ⊦ gstore1[n0] = gstore0[n, gstore1[n]][n0]

Proof step 13 from proof gstore-dom-eq-hole (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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