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Proof step 5 from proof in-nodes-down-at-same (previous step)

m ∈ gstore, @(m0, m1) ∈ gstore[m] ↓.ladrlist ⊦ gstore ↓[@(m, m0, m1)] = gstore[@(m, m0, m1)], m ∈ ginval

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 6:
gstore[m] ↓ = groupblock(gndx, lax, m2), @(m0, m1) ∈ lax, m ∈ gstore ⊦ gstore ↓[@(m, m0, m1)] = gstore[@(m, m0, m1)], m ∈ ginval

Rule argument

spec: ablock, inst: group-store name: elim seq: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m) subst: [gblock, gndx, lax, m] → [gstore[m] ↓, gndx, lax, m2]

Additional information

Used simplifier rules: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m); (elim) Used terms: gstore[m] ↓, gndx, lax, m2