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Proof step 2 from proof in-restr-eq-notin-log (previous step)

ax.toSet = as | n ⊦ ax.toSet ∩ abs-log(nx, gstore).toSet = ∅, n ∈ nx

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: abs-log-toset-inter-restr-empty: ⊦ ¬ n ∈ nx → abs-log(nx, gstore).toSet ∩ (as | n) = ∅;% ⊦ # ∅ = 0; (s)%int-c: ⊦ as ∩ as0 = as0 ∩ as; from specification set-union[node-store]%int-a: ⊦ (as ∩ as0) ∩ as1 = as ∩ as0 ∩ as1; from specification set-union[node-store]%size-zero-01: ⊦ as ≠ ∅ → # as ≠ 0; (forward) from specification set-basic[node-store]