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Proof step 3 from proof in-restr-notin-log (previous step)

ax.toSet ⊆ as | n ⊦ #(ax.toSet ∩ abs-log(nx, gstore).toSet) = 0, ax.toSet ∩ abs-log(nx, gstore).toSet = ∅, n ∈ nx

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ as = as0 ↔ (∀ adr. adr ∈ as ↔ adr ∈ as0)
Proof step 5:
ax.toSet ⊆ as | n ⊦ #(ax.toSet ∩ abs-log(nx, gstore).toSet) = 0, n ∈ nx, ∀ adr. adr ∈ ax.toSet ∩ abs-log(nx, gstore).toSet ↔ adr ∈ ∅

Rule argument

spec: set-basic, inst: node-store name: Extension seq: ⊦ as = as0 ↔ (∀ adr. adr ∈ as ↔ adr ∈ as0) subst: [as0, as] → [∅, ax.toSet ∩ abs-log(nx, gstore).toSet] flags: <all paths>

Additional information

Used terms: ∅, ax.toSet ∩ abs-log(nx, gstore).toSet