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Proof step 2 from proof index-update-adr-in (previous step)

# kx = # ax ⊦ adr ∈ ri[kx, ax] ↔ adr ∈ ax ∨ adr ∈ range(ri \ kx.toSet), dups(kx)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
# kx = # ax ⊦ adr ∈ ri[kx, ax] ↔ adr ∈ ax ∨ adr ∈ ri \ kx.toSet, dups(kx)

Rule argument

Additional information

Used simplifier rules: ⊦ adr ∈ range ri ↔ adr ∈ ri; (s)