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Proof step 25 from proof index-update-adr-in (previous step)

# kx0 = # ax1, adr = adr1 ∨ adr ∈ (ri \ kx0.toSet) -- key ⊦ dups(kx0), adr ∈ ri[key, adr1][kx0, ax1], key ∈ kx0, adr ∈ ax1, adr ∈ ri[key, adr1] \ kx0.toSet

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 2

Additional information