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Proof step 13 from proof keys-nodes-in-ri (previous step)

adr ∈ ax ↔ adr ∈ range ri | n, ri-cons(ri, fs), adr ∈ ax ⊦ fs[adr].key ∈ ri

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
ri-cons(ri, fs), adr ∈ ri, adr ∈ ax ⊦ fs[adr].key ∈ ri

Rule argument

Additional information

Used simplifier rules: ⊦ adr ∈ range ri ↔ adr ∈ ri; (s)% ⊦ adr ∈ as | n ↔ adr.lnum = n ∧ adr ∈ as; (ws)