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Proof step 5 from proof keys-nodes-in-ri (previous step)

ax.toSet = range ri | n, ri-cons(ri, fs) ⊦ ∀ key. key ∈ keys(fs, ax).toSet → key ∈ dom ri

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
ax.toSet = range ri | n, ri-cons(ri, fs), key ∈ keys(fs, ax) ⊦ key ∈ ri

Rule argument

Additional information

Used simplifier rules: ⊦ key ∈ dom ri ↔ key ∈ ri; (s)% ⊦ key ∈ kx.toSet ↔ key ∈ kx; (s)