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Proof step 13 from proof keys-remove-leb (previous step)

ri-cons(ri0[key, @(n, m0, m1)], fs), ∀ adr. adr ∈ ax.toSet ↔ adr ∈ (range ri0 | n) ++ @(n, m0, m1) ⊦ key ∈ ri0, @(n, m0, m1) ∈ ax ∧ fs[@(n, m0, m1)].key = key

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
ri-cons(ri0[key, @(n, m0, m1)], fs), ∀ adr. adr ∈ ax ↔ adr = @(n, m0, m1) ∨ adr ∈ range ri0 | n ⊦ key ∈ ri0, @(n, m0, m1) ∈ ax ∧ fs[@(n, m0, m1)].key = key

Rule argument

Additional information

Used simplifier rules: ⊦ adr ∈ as ++ adr0 ↔ adr = adr0 ∨ adr ∈ as; (s)% ⊦ adr ∈ ax.toSet ↔ adr ∈ ax; (s)