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Proof step 2 from proof keys-remove-leb (previous step)

ax.toSet = range ri | n, ri-cons(ri, fs), @(n, m0, m1) ∈ ri \ keys(fs, ax).toSet ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ adr ∈ ri ↔ (∃ key. key ∈ ri ∧ ri[key] = adr)
Proof step 4:
ax.toSet = range ri | n, ri-cons(ri, fs), ∃ key. key ∈ ri \ keys(fs, ax).toSet ∧ (ri \ keys(fs, ax).toSet)[key] = @(n, m0, m1) ⊦

Rule argument

spec: store+set, inst: node-index name: Data-in seq: ⊦ adr ∈ ri ↔ (∃ key. key ∈ ri ∧ ri[key] = adr) subst: [ri, adr] → [ri \ keys(fs, ax).toSet, @(n, m0, m1)] flags: <all paths>

Additional information

Used terms: ri \ keys(fs, ax).toSet, @(n, m0, m1)