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Proof step 20 from proof keys-remove-leb (previous step)

key-cons(key, fs[@(n, m0, m1)]), @(n, m0, m1) ∈ ax, @(n, m0, m1) ∈ fs ⊦ fs[@(n, m0, m1)].key = key, key ∈ ri0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: aubifs-inv name: key-cons seq: ⊦ key-cons(key, nd) ↔ nd.key = key ∧ (key.inode? → nd.inode? ∧ key.ino ≠ 0) ∧ (key.dentry? → nd.dentry?) ∧ (key.data? → nd.data?) subst: [nd, key] → [fs[@(n, m0, m1)], key] flags: <all paths>

Additional information

Used terms: fs[@(n, m0, m1)], key