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Proof step 24 from proof keys-same-fs (previous step)

fs0 | (ax.toSet ++ adr) = fs1 | (ax.toSet ++ adr) ⊦ fs0 | ax.toSet = fs1 | ax.toSet, fs0[adr].key = fs1[adr].key ∧ keys(fs0, ax) = keys(fs1, ax)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: store, inst: node-store name: Extension seq: ⊦ fs = fs0 ↔ (∀ adr. (adr ∈ fs ↔ adr ∈ fs0) ∧ fs[adr] = fs0[adr]) subst: [fs0, fs] → [fs1 | (ax.toSet ++ adr), fs0 | (ax.toSet ++ adr)] flags: <all paths>

Additional information

Used terms: fs1 | (ax.toSet ++ adr), fs0 | (ax.toSet ++ adr)