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Proof step 21 from proof lebs-dom-remove-refsize0 (previous step)

(∅)[m] = groupblock(gndx, lax, m2), ri[key] = @(m, m0, m1), inv(gstore \ ginval), key ∈ ri, ∀ key. key ∈ ri → ri[key] ∈ nodes(gstore ↓, ginval) ∧ key-cons(key, nodes(gstore ↓, ginval)[ri[key]]) ⊦ m ∈ remove-refsize0(gstore), m ∈ gstore

User applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: key abort: F discard: T computed: T

Additional information

Used simplifier rules: nodes-gstore-in: ⊦ adr ∈ nodes(gstore, ginval) ↔ ¬ ¬(adr ∈ gstore ∧ ¬ adr.lnum ∈ ginval);%down-store-adr-in-explicit: ⊦ @(m0, m1, m2) ∈ gstore ↓ ↔ m0 ∈ gstore ∧ @(m1, m2) ∈ gstore ↓[m0].ladrlist; Used terms: key