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Proof step 3 from proof new-prefixn (previous step)

new(ax, fs) ⊦ new(prefixn(n, ax), fs)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ prefixn(n, ax) = (n ≤ # ax ⊃ firstn(n, ax);ax)
Proof step 5:
new(ax, fs) ⊦ new((n ≤ # ax ⊃ firstn(n, ax);ax), fs)

Rule argument

spec: list-prefixn, inst: address-list-set name: prefixn seq: ⊦ prefixn(n, ax) = (n ≤ # ax ⊃ firstn(n, ax);ax) subst: [ax, n] → [ax, n] flags: <all paths>

Additional information

Used terms: ax, n