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Proof step 16 from proof nodes-allocate (previous step)

gstore[m, groupblock([], [], m0)][m1] = groupblock(gndx, lax, m4) ⊦ m ∈ gstore, ( (m1 = m ∨ m1 ∈ gstore) ∧ @(m2, m3) ∈ lax ∧ (m1 = m ∨ ¬ m1 ∈ ginval) → (@(m1, m2, m3).lnum ∈ gstore ∧ @(@(m1, m2, m3).pos, @(m1, m2, m3).size) ∈ gstore[@(m1, m2, m3).lnum].ladrlist) ∧ ¬ m1 ∈ ginval) ∧ ( (m1 = m ∨ m1 ∈ gstore) ∧ @(m2, m3) ∈ lax ∧ (m1 = m ∨ ¬ m1 ∈ ginval) → nodes(gstore[m, groupblock([], [], m0)], ginval -- m)[@(m1, m2, m3)] = nodes(gstore, ginval)[@(m1, m2, m3)])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
gstore[m, groupblock([], [], m0)][m1] = groupblock(gndx, lax, m4) ⊦ m ∈ gstore, ((m1 = m ∨ m1 ∈ gstore) ∧ @(m2, m3) ∈ lax ∧ (m1 = m ∨ ¬ m1 ∈ ginval) → m1 ∈ gstore ∧ @(m2, m3) ∈ gstore[m1].ladrlist ∧ ¬ m1 ∈ ginval) ∧ ( (m1 = m ∨ m1 ∈ gstore) ∧ @(m2, m3) ∈ lax ∧ (m1 = m ∨ ¬ m1 ∈ ginval) → nodes(gstore[m, groupblock([], [], m0)], ginval -- m)[@(m1, m2, m3)] = nodes(gstore, ginval)[@(m1, m2, m3)])

Rule argument

Additional information

Used simplifier rules: ⊦ @(m, m0, m1).size = m1; (s)% ⊦ @(m, m0, m1).pos = m0; (s)% ⊦ @(m, m0, m1).lnum = m; (s)