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Proof step 19 from proof nodes-allocate (previous step)

gstore[m1] = groupblock(gndx0, lax0, m5), gstore[m, groupblock([], [], m0)][m1] = groupblock(gndx, lax, m4) ⊦ m1 = m, m ∈ gstore, ((m1 = m ∨ m1 ∈ gstore) ∧ @(m2, m3) ∈ lax ∧ (m1 = m ∨ ¬ m1 ∈ ginval) → m1 ∈ gstore ∧ @(m2, m3) ∈ lax0 ∧ ¬ m1 ∈ ginval) ∧ ( (m1 = m ∨ m1 ∈ gstore) ∧ @(m2, m3) ∈ lax ∧ (m1 = m ∨ ¬ m1 ∈ ginval) → nodes(gstore[m, groupblock([], [], m0)], ginval -- m)[@(m1, m2, m3)] = nodes(gstore, ginval)[@(m1, m2, m3)])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
gstore[m1] = groupblock(gndx0, lax0, m5), m1 ∈ gstore, @(m2, m3) ∈ lax0 ⊦ nodes(gstore[m, groupblock([], [], m0)], ginval -- m)[@(m1, m2, m3)] = nodes(gstore, ginval)[@(m1, m2, m3)], m ∈ gstore, m1 ∈ ginval

Rule argument

Additional information

Used simplifier rules: ⊦ groupblock(gndx, lax, m) = groupblock(gndx0, lax0, m0) ↔ gndx = gndx0 ∧ lax = lax0 ∧ m = m0; (ws)% ⊦ n ≠ n0 → gstore[n0, gblock][n] = gstore[n]; (s)