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Proof step 12 from proof nodes-append-subseteq-nodown (previous step)

# gndx = # lax, # gndx1 = # lax1, gstore[n] = groupblock(gndx, lax, m0), gstore[m] ↓ = groupblock(gndx0, lax0, m3), n ∈ gstore, m ∈ gstore, @(m1, m2) ∈ lax0, m ∈ gstore ↓[n, groupblock(gndx + gndx1, lax + lax1, m0)] ⊦ m ∈ ginval, nodes(gstore ↓, ginval)[@(m, m1, m2)] = nodes(gstore ↓[n, groupblock(gndx + gndx1, lax + lax1, m0)], ginval)[@(m, m1, m2)] ∧ @(m1, m2) ∈ gstore ↓[n, groupblock(gndx + gndx1, lax + lax1, m0)][m].ladrlist

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 13:
# gndx1 = # lax1, # gndx = # lax, gstore[n] = groupblock(gndx, lax, m0), gstore ↓[n, groupblock(gndx + gndx1, lax + lax1, m0)][m] = groupblock(gndx2, lax2, m4), gstore[m] ↓ = groupblock(gndx0, lax0, m3), m ∈ gstore ↓[n, groupblock(gndx + gndx1, lax + lax1, m0)], @(m1, m2) ∈ lax0, m ∈ gstore, n ∈ gstore ⊦ m ∈ ginval, nodes(gstore ↓, ginval)[@(m, m1, m2)] = nodes(gstore ↓[n, groupblock(gndx + gndx1, lax + lax1, m0)], ginval)[@(m, m1, m2)] ∧ @(m1, m2) ∈ lax2

Rule argument

spec: ablock, inst: group-store name: elim seq: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m) subst: [gblock, gndx, lax, m] → [gstore ↓[n, groupblock(gndx + gndx1, lax + lax1, m0)][m], gndx2, lax2, m4]

Additional information

Used simplifier rules: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m); (elim) Used terms: gstore ↓[n, groupblock(gndx + gndx1, lax + lax1, m0)][m], gndx2, lax2, m4