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Proof step 15 from proof nodes-append-subseteq-nodown (previous step)

# gndx = # lax, # gndx1 = # lax1, gstore ↓[n, groupblock(gndx + gndx1, lax + lax1, m0)][m] = groupblock(gndx2, lax2, m4), gstore[n] = groupblock(gndx, lax, m0), gstore[m] ↓ = groupblock(gndx0, lax0, m3), n ∈ gstore, m ∈ gstore, @(m1, m2) ∈ lax0, m ∈ gstore ↓[n, groupblock(gndx + gndx1, lax + lax1, m0)], @(m, m1, m2) ∈ nodes(gstore ↓, ginval) ⊦ m ∈ ginval, gstore ↓[@(m, m1, m2)].nd = nodes(gstore ↓[n, groupblock(gndx + gndx1, lax + lax1, m0)], ginval)[@(m, m1, m2)] ∧ @(m1, m2) ∈ lax2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
# gndx1 = # lax1, # gndx = # lax, gstore[n] = groupblock(gndx, lax, m0), gstore ↓[n, groupblock(gndx + gndx1, lax + lax1, m0)][m] = groupblock(gndx2, lax2, m4), gstore[m] ↓ = groupblock(gndx0, lax0, m3), m ∈ gstore ↓[n, groupblock(gndx + gndx1, lax + lax1, m0)], @(m1, m2) ∈ lax0, m ∈ gstore, n ∈ gstore ⊦ m ∈ ginval, gstore ↓[@(m, m1, m2)].nd = nodes(gstore ↓[n, groupblock(gndx + gndx1, lax + lax1, m0)], ginval)[@(m, m1, m2)] ∧ @(m1, m2) ∈ lax2

Rule argument

Additional information

Used simplifier rules: nodes-gstore-in: ⊦ adr ∈ nodes(gstore, ginval) ↔ ¬ ¬(adr ∈ gstore ∧ ¬ adr.lnum ∈ ginval);%down-store-adr-in-explicit-simp: ⊦ gstore[m0] ↓ = groupblock(gndx, lax, n0) ∧ @(m1, m2) ∈ lax → (@(m0, m1, m2) ∈ gstore ↓ ↔ m0 ∈ gstore ↓);%down-store-in: ⊦ n ∈ gstore ↓ ↔ n ∈ gstore;% ⊦ @(m, m0, m1).lnum = m; (s)