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Proof step 4 from proof nodes-dealloc (previous step)

⊦ (adr ∈ gstore ∧ adr.lnum ≠ n ∧ ¬ adr.lnum ∈ ginval ↔ adr ∈ nodes(gstore, ginval) \ (dom nodes(gstore, ginval) | n)) ∧ ( adr ∈ gstore -- n ∧ adr.lnum ≠ n ∧ ¬ adr.lnum ∈ ginval → nodes(gstore -- n, ginval ++ n)[adr] = (nodes(gstore, ginval) \ (dom nodes(gstore, ginval) | n))[adr])

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 5:
adr = @(m, m0, m1) ⊦ (adr ∈ gstore ∧ m ≠ n ∧ ¬ m ∈ ginval ↔ adr ∈ nodes(gstore, ginval) \ (dom nodes(gstore, ginval) | n)) ∧ (adr ∈ gstore -- n ∧ m ≠ n ∧ ¬ m ∈ ginval → nodes(gstore -- n, ginval ++ n)[adr] = (nodes(gstore, ginval) \ (dom nodes(gstore, ginval) | n))[adr])

Rule argument

spec: address-data name: elim seq: ⊦ (m = adr.lnum ∧ m0 = adr.pos) ∧ m1 = adr.size ↔ adr = @(m, m0, m1) subst: [adr, m, m0, m1] → [adr, m, m0, m1]

Additional information

Used simplifier rules: ⊦ (m = adr.lnum ∧ m0 = adr.pos) ∧ m1 = adr.size ↔ adr = @(m, m0, m1); (elim) Used terms: adr, m, m0, m1