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Proof step 11 from proof nodes-ginval-rem-01 (previous step)

dom gstore1 ∪ ns = dom gstore ⊦ (m ∈ gstore ∧ @(m0, m1) ∈ gstore[m].ladrlist → (¬ m ∈ ginval \ dom gstore1 \ dom gstore ↔ ¬ m ∈ ginval)) ∧ ( m ∈ gstore ∧ @(m0, m1) ∈ gstore[m].ladrlist ∧ ¬ m ∈ ginval \ dom gstore1 \ dom gstore → nodes(gstore, ginval \ dom gstore1 \ dom gstore)[@(m, m0, m1)] = nodes(gstore, ginval)[@(m, m0, m1)])

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 12:
gstore[m] = groupblock(gndx, lax, m2), dom gstore1 ∪ ns = dom gstore ⊦ (m ∈ gstore ∧ @(m0, m1) ∈ lax → (¬ m ∈ ginval \ dom gstore1 \ dom gstore ↔ ¬ m ∈ ginval)) ∧ ( m ∈ gstore ∧ @(m0, m1) ∈ lax ∧ ¬ m ∈ ginval \ dom gstore1 \ dom gstore → nodes(gstore, ginval \ dom gstore1 \ dom gstore)[@(m, m0, m1)] = nodes(gstore, ginval)[@(m, m0, m1)])

Rule argument

spec: ablock, inst: group-store name: elim seq: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m) subst: [gblock, gndx, lax, m] → [gstore[m], gndx, lax, m2]

Additional information

Used simplifier rules: ⊦ (gndx = gblock.gndlist ∧ lax = gblock.ladrlist) ∧ m = gblock.ref-size ↔ gblock = groupblock(gndx, lax, m); (elim) Used terms: gstore[m], gndx, lax, m2