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Proof step 19 from proof nodes-no-change-eq (previous step)

m ∈ gstore0 ↔ m ∈ gstore1, gstore0[m] = groupblock(gndx0, lax0, m3), gstore1[m] = groupblock(gndx, lax, m2), m ∈ gstore1, @(m0, m1) ∈ lax0, m ∈ gstore1 → gndx = gndx0 ∧ lax = lax0 ⊦ nodes(gstore0, ginval)[@(m, m0, m1)] = nodes(gstore1, ginval)[@(m, m0, m1)], m ∈ ginval

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
gstore0[m] = groupblock(gndx0, lax0, m3), gstore1[m] = groupblock(gndx0, lax0, m2), m ∈ gstore0, m ∈ gstore1, @(m0, m1) ∈ lax0 ⊦ nodes(gstore0, ginval)[@(m, m0, m1)] = nodes(gstore1, ginval)[@(m, m0, m1)], m ∈ ginval

Proof step 19 from proof nodes-no-change-eq (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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